Question

show that 9^ n cannot end with the digit 2 4 natural number N

Answer 1

We know that a no ending with 2 4 should have 2 as one of its factor. Eg-
24= 2x2x2x3
4 =2 x2
Now by fundamental theorem of arithmetic we have
9^n = (3 x3) ^n
= 3^n x 3^n
Here we see that 9^n does not have 2 as one of its factors. Therefore 9^n cannot end in 2,4.

Answer 2

show that 9^ n cannot end with the digit 2 4 natural number N

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