Question

show that 9 power n can't with the digit 2 for any number n​

Answer 1

Answer:

We can see prime factorization on 9^n does not contain 2. Hence it can't end with 2. to end with number 2, 9n show divisible by 2 and the prime factorisation of 9n should cannot the number 2 but the prime factorisation of 9n will be 1 and 3 thus cannot end with digit 2 for any natural number.

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