Question

show that 9 raise to power n cannot end with 3 for any natural number N

Answer 1

Solution :-

》given by condition:- 9^n

according to question :-

》natural numbers (n= 0,1,2,3,4..... n )

》if n=0 then 9^0 = 1

》if n= 1 then 9^1 = 9

》if n=2 then 9^2 = 81

similarly

》if n= 3 then 9^3 = 729

》proved that that 9 raise to power n cannot end with 3 for any natural number N.

☆i hope its help☆