Show that 9n can never end with digit zero for any natural number n
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6
by fundamental theorem of arithmetic
no. ending with 0 should have (2×5)^n as its factor
since 9^n=(3×3)^n
it doesn't have (2×5)^n as its factor
hence 9^n can never end with 0
H.P.
no. ending with 0 should have (2×5)^n as its factor
since 9^n=(3×3)^n
it doesn't have (2×5)^n as its factor
hence 9^n can never end with 0
H.P.
Answered by
4
Answer:
her is ur answer in the pic
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