Show that 9n can not end with digit 0 for any natural number n.
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Answered by
3
Answer:
Since prime factorisation of 9n is given by 9n= (3 x 3)n = 3271.
Prime factorisation of 9″ contains only prime number 3.
9 may end with the digit 0 for some natural number V if 5 must be in its prime factorisation, which is not present.
So, there is no natural number N for which 9n ends with the digit zero.
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Answered by
3
Answer:
"9n can never end with the digit 0 for any natural number n because for a number to end with zero it should be divisible by 10 and therefore its factors should be 5 and 2. But as 9 has only 3 as its factor, increasing its power will not make 5 as its factor. Thus it can never end with 0."
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