Question

show that:(9p-5q)^+180pq=(9p+5q)^​

Answer 1

ANSWER

(9p−5q)

2

+180pq=(9p+5q)

2

LHS=(9p)

2

−2(9p)(5q)+(5q)

2

+180pq

=81p

2

−90pq+25q

2

+180pq

=81p

2

+90pq+25q

2

RHS=(9p+5q)

2

=(9p)

2

+2(9p)(5q)+(5q)

2

=81p

2

+90pq+25q

2

LHS=RHS

I hope it helps you.

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Answer 2

Given :-

• $(9p - 5q)² + 180pq = (9p + 5q)²$

Solution :-

$\implies LHS \: = (9p \: - \: 5q) {}^{2} \: + \: 180 \: pq$

$\implies (9p) {}^{2} \: - \: 2 \: \times \: 9p \: \times \: 5q \: + \: (5q) {}^{2} \: + \: 180pq$

$\implies(9p) {}^{2} \: - \: 90pq \: + \: (5q) {}^{2} \: + \: 180pq$

$\implies \: (9p) {}^{2} \: + \: 90pq \: + \: (5q) {}^{2}$

$\implies \: RHS \: = (9p \: + \: 5q) {)}^{2}$

$\implies \: LHS = RHS$