show that [9p-5q]^2 + 180 pq=[9p + 5q] ^2
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Answer:(9p−5q)2+180pq=(9p+5q)2
LHS=(9p)2−2(9p)(5q)+(5q)2+180pq
=81p2−90pq+25q2+180pq
=81p2+90pq+25q2
RHS=(9p+5q)2
=(9p)2+2(9p)(5q)+(5q)2
=81p2+90pq+25q2
LHS=RHS
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