Math, asked by aryan9798ku, 26 days ago

Show that 9v cannot end with zero for any natural number Y

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Answered by deveshkumar9563

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If any number ends with 0 then it must be divisible by 5

Hence its prime factorization must contain 5

But we know 4=2×2

So, there is no natural number n for which 4n can end with 0.

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