show that A( 0, 0) B(5, 5) and c(-5 , 5) are the vertices of a right angled isocles triangr
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Let the vertices of the right isosceles triangle be A(0,0),B(5,5),C(-5,5)
AB=
25+25
=
50
BC=
(5+5)
2
+(5−5)
2
=
100
=10
AC=
(−5−0)
2
+(5−0)
2
=
50
∴AB=AC=
50
∴ △ABC is an isosceles right angled
Also, AB
2
+AC
2
=BC
2
⇒50+50=100
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