Question

show that A(0,0) , B(5,5) , C(-5,5) are vertices of right angled isosceles triangle. Find the area also​

Answer 1

ANSWER

Let the vertices of the right isosceles triangle be A(0,0),B(5,5),C(-5,5)

AB=25+25=50

BC=(5+5)2+(5−5)2=100=10

AC=(−5−0)2+(5−0)2=50

∴AB=AC=50

∴ △ABC is an isosceles right angled

Also, AB2+AC2=BC2

⇒50+50=100

△ABC is an isosceles right-angled triangle.