Question

show that A (1, 1 ) B (3, 2) and C (5, 3) are not the vertices of triangle​

Answer 1

Step-by-step explanation:

area of these coordinate is zero so it cannot be the vertices of triangle

Answer 2

Answer:

the given coordinates,

A(1,1)

B(3,2)

C(5,3)

Now,

area of the triangle ∆ABC

$= \frac{1}{2} | \binom{1}{1} \binom{3}{2} \binom{5}{3} \binom{1}{1} | \\ = \frac{1}{2} ((2 + 9 + 5) - (3 + 10 + 3)) \\ = \frac{1}{2} (16 - 16) \\ = \frac{1}{2} \times 0 \\ = 0$

the area of the triangle was 0.

so it can only explain that no triangle was formed.

so these are not the vertices of a triangle