Question

show that : (a+1/b)^m × (a-1/b)^n / (b+1/a)^m × (b-1/a)^n = (a/b)^m+n​

Answer 1

Answer:

(a-1/b)^n / (b+1/a)^m × (b-

Step-by-step explanation:

show that : (a+1/b)^m × (a-1/b)^n / (b+1/a)^m × (b-1/a)^n = (a/b)^m+n