Question

Show that a⁰ = 1 so logₐ1=0.

Answer 1

${x}^{y} \div {x}^{y} = {x}^{y - y} = {x}^{0} = 1$
any number raised to the power of x divided by the same number raised to x will be 1 ( any number divided by itself is 1 ) and hence
$log_{a}(1) = 0$