show that a= 2i+3j-4k and b=2i+4j+4k are perpendicular to each other
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we know that if two vectors are perpendicular then their dot product is zero
thus A.B=(2i+3j-4k).(2i+4j+4k)=4i^2+12j^2-16k^2
but i^2=j^2=k^2=1
thus A.B=4+12-16=16-16=0
hence as the dot product of vector a nd b js zero and neither a nor b is zero hence a and b are perpendicular to each other
thus A.B=(2i+3j-4k).(2i+4j+4k)=4i^2+12j^2-16k^2
but i^2=j^2=k^2=1
thus A.B=4+12-16=16-16=0
hence as the dot product of vector a nd b js zero and neither a nor b is zero hence a and b are perpendicular to each other
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