Question

Show that A (4,1), B (5,-2) and c (6,-5) are collinear. [Note: slope of AB = slope of BC= slope of AC​​

Answer 1

Answer:

(i) Slope of AB=

5−4

12−8

=

1

4

=4

Slope of BC=

9−5

28−12

=

4

16

=4

Hence AB∣∣BC, but B is a point of intersect.

Hence A, B, C are collinear.

(ii) Slope of AB=

3−16

−6+18

=

−13

12

=−

13

12

Slope of BC=

−10−3

6+6

=

−13

12

=−

13

12

Slope of AB= slope of BC

Hence A, B, C are collinear.

Step-by-step explanation:

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