show that A(4, -1), B(6, 0), C(7,-2) and D(5,-3) are the vertices of a square.
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Answer:
Hope it helps.
Step-by-step explanation:
Distance between AB = √5
Distance between BC = √5
Distance between CD = √5
Distance between DA = √5
All sides are equal because AB = Bc = CD = DA
Now , AD = √5 ; BC = √5
So diagonals are also equal .
So ABCD is a square.
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