Question

show that A(8, -4), B(9, 5) and C(0,4) as Isosceles triangle
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Answer 1

Distance formula=√(x2-x1)^2+(y2-y1)^2

if two sides are equal and one side is not equal then it is isosceles triangle

AB=√(9-8)^2+(5-(-4)^2

AB=√1+81

AB=√82

AC=√(0-8)^2+(4-(-4)^2

AC=√64+64

AC=√128

BC=√(0-9)^2+(4-5)^2

BC=√81+1

BC=√82

so AB=BC so triangle is isosceles triangle