Show that A(a,b+c),B(b,c+a) and C(c,a+b) are colinear
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The three points A(a,b+c), B(b,c+a) and C(c,a+b) are colinear, it is proves.
Step-by-step explanation:
Here, A(x_1 = a, y_1 = b + c), B(x_2 = b, y_2 = c + a) and
C(x_3 = c, y_3 = a + b)
If the tree points are coinear, then area of triangle is zero.
∴ x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) = 0
⇒ a(c + a - a - b) + b(a + b - b - c) + c(b + c - c - a) = 0
⇒ a(c - b) + b(a - c) + c(b - a) = 0
⇒ ac - ab + ba - bc + cb - ac = 0
⇒ 0 = 0, it is proved.
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