Question

show that a,...a....form an Ap where an is defined below
an=3+4n​

Answer 1

Step-by-step explanation:

a1= 3+4=7

a2=3+8=11

a3=3+12=15

d = a2-a1= 11-7=4

d=a3-a2=15-11=4

there the common different is equal so the given form is in AP

Answer 2

Question:

Show that a,...a....form an Ap where an is defined below an=3+4n

Solution:

First of all find the first term, a.

So, for an = 3 + 4n

answer️ a1 = 3 + 4(1) = 7

Now find the 2nd term(T2) :-

➡️a2 = 3 + 4(2) = 11

So, common difference (d) = 11 - 7 = 4

Third term(T3) :-

a3 = 3 + 4(3) = 15

Again d = 15 - 11 = 4.

Since the common difference is same hence it is an Arithmetic Progression.