Question

Show that (a+b)^2=(a-b)^2+4ab

Answer 1

Answer:

LHS

Step-by-step explanation:

( a + b )² = a² + 2ab + b²

now

RHS

( a - b )² + 4ab

= a² - 2ab + b² + 4ab

= a² + 2ab + b²

hence, LHS = RHS

Answer 2

Answer:

(a+b)^2= (a-b)^2+4ab

a^2+b^2+2ab= a^2+b^2-2ab +4ab

a^2+b^2+2ab= a^2+b^2-2ab

reaarnging like terms

a^2+b^2= a^2+b^2-2ab-2ab

a^2+b^2= a^2+b^2-4ab

hence proved