show that (a-b)²,(a²+b²) and (a+b)² are in AP
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Answered by
2
Answer:
your ans
Step-by-step explanation:
Assume that (a−b)
2
,(a
2
+b
2
) and (a+b)
2
are in AP.
So, difference between two consecutive terms will be same.
(a
2
+b
2
)−(a−b)
2
=(a+b)
2
−(a
2
+b
2
)
(a
2
+b
2
)−(a
2
+b
2
−2ab)=a
2
+b
2
+2ab−a
2
−b
2
2ab=2ab
Which is true.
Hence given terms are in AP.
Answered by
1
Step-by-step explanation:
The steps are given above in the picture attached
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