Question

show that (a-b) ², (a²+b²) and (a+b) ² are in AP

Answer 1

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Answer 2

Answer:

To show, (a-b)², (a²+b²) and (a+b)² are in AP.

d2-d1 = d3-d2

(a²+b²) - (a-b)² = (a+b)² - (a²+b²)

a²+b²-a²+b²-2ab = a²+b²-2ab-a²+b²

-2ab = -2ab

2ab = 2ab

Hence Proved