Math, asked by nainanaina03127, 1 month ago


Show that [a-b]², [a²+b²] and [a+b]²
are in Ap [ Arithmetic Progresion]​

Answers

Answered by AnwitS
0

Answer:

Please see the explanation.Hope,it will help you to get your answer.

Step-by-step explanation:

From A.P theory,we can write for 3 numbers in A.P.

2 × (Middle term) = First Term + Last Term

Let, Add First & Last Term

(a-b)^2 + (a+b)^2

= 2 (a^2 + b^2)

The value is equals to twice of second term.

So,we can say that [a - b]^2 , [a^2 + b^2] , [a + b]^2 are in A.P.

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