Show that [a-b]², [a²+b²] and [a+b]²
are in Ap [ Arithmetic Progresion]
Answers
Answered by
0
Answer:
Please see the explanation.Hope,it will help you to get your answer.
Step-by-step explanation:
From A.P theory,we can write for 3 numbers in A.P.
2 × (Middle term) = First Term + Last Term
Let, Add First & Last Term
(a-b)^2 + (a+b)^2
= 2 (a^2 + b^2)
The value is equals to twice of second term.
So,we can say that [a - b]^2 , [a^2 + b^2] , [a + b]^2 are in A.P.
Similar questions