Question

show that (a-b)^2=(b-a)^2

Answer 1

(a-b)²
=a²+b²-2ab
also be written as
(b)²+(-a)²-2ab
=(b-a)²

Answer 2

(a-b)^2 = (b-a)^2

(a-b)^2 = a^2 + b^2 -2ab
(b-a)^2 = b^2 + a^2 - 2ba

Equating both with each other..

a^2 + b^2 -2ab = b^2 + a^2 -2ab

Where a^2 = a^2
b^2 = b^2
-2ab=-2ab