Show that (a-b)^3+(b-c)^3+(c-a)^3=3(a-b)(b-c)(c-a).
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Let x = a-b
y = b-c
z = c-a
For x + y + z = 0
x^3 + y^3 + z^3 = 3 xyz
Since a-b+b-c+c-a = 0
The given equation is satisfied,
Hence,
(a-b)^3+(b-c)^3+(c-a)^3=3(a-b)(b-c)(c-a).
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