Question

show that (a-b)^3+(b-c)^3+(c-a)^3=3(a-b)(b-c)(c-a)​

Answer 1

Answer:

here is your answer

Step-by-step explanation:

As we know if

x+y+z=0

this implies

x^3+y^3+z^3 =3xyz

So here we can take

(a-b) =x

(b-c)=y

(c-a) =z

Again we have

x+y+z=0 As (a-b) +(b-c) +(c-a)=0

so this implies

x^3+y^3+z^3=3xyz

Or

(a-b)^3 +(b-c)^3 +(c-a)^3 = 3(a-b)(b-c)(c-a)

Hope you understood.

Cheers