Show that (a - b)³ + ( b - c )³ + ( c - a )³ = 3 ( a - b ) ( b -c ) ( c - a )?
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=(a-b)³+(b-c)³+ (c-a)³
=a³-b³- 3ab(a-b) +b³-c³ - 3bc(b-c) + c³-a³-3ac(a-c)
=a³-a³+ b³-b³ +c³ -c³ - 3ab(a-b)- 3bc(b-c)-3ac(a-c)
= 3 (a - b)(b -c) (c-a)
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