Show that a-b,a,a+b From consecutive terms of an A.P.?
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Answered by
4
Answer:
In an A.P.,
2nd Term - 1st Term = 3rd Term - 2nd Term
Here,
1st Term = a-b
2nd Term = a
3rd Term = a+b
LHS
a-(a-b) = a-a+b
= b
RHS
a+b-a = b
∵ LHS = RHS,
∴ The terms are in A.P.
Answered by
5
In an AP we know that 2 times of second term =1st term + 3rd term i.e 2a =a-b+a+b i.e 2a=2a. So given terms are in AP
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