Show that (a-b) (a+b)+(b-c) (b+c) +(c+a) =0
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Step-by-step explanation:
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Step-by-step explanation:
I guess you missed some part in the question.
the question might be, (a-b)(a+b) + (b-c)(b+c) + (c+a)(c-a)
I am assuming this be the question.
hence
(a-b)(a+b) + (b-c)(b+c) + (c+a)(c-a)
Now (a-b)(a+b) = a² - b²
=> (a-b)(a+b) + (b-c)(b+c) + (c+a)(c-a)
=> a² - b² + b² - c² + c² - a²
=> 0
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