Math, asked by vanshthapa1, 7 months ago

Show that (a-b) (a+b)+(b-c) (b+c) +(c+a) =0​

Answers

Answered by sakshithakur90
0

Step-by-step explanation:

Please mark me as brailiest answer

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Answered by shubhshubham14
1

Step-by-step explanation:

I guess you missed some part in the question.

the question might be, (a-b)(a+b) + (b-c)(b+c) + (c+a)(c-a)

I am assuming this be the question.

hence

(a-b)(a+b) + (b-c)(b+c) + (c+a)(c-a)

Now (a-b)(a+b) = a² - b²

=> (a-b)(a+b) + (b-c)(b+c) + (c+a)(c-a)

=> a² - b² + b² - c² + c² - a²

=> 0

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