Question

show that
(a-b) (a+b) + (b-c) (b+c) + (c-a) (c+a)=0​

Answer 1

Answer:

(a-b) (a+b) + (b-c) (b+c) + (c-a) (c+a)=0

Step-by-step explanation:

=a^2 - b^2 + b^2 - c^2 + c^2 - a^2

=a^2 - a^2 - b^2 + b^2 -c^2 + c^2

=0