Question

show that (a-b)(a+b) + (b-c)(b+c ) + (c-a) (c+a) =0

Answer 1

(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)
=(a²-b²)+(b²-c²)+(c²-a²)
From(x+y)(x-y)=x²-y²
=a²-b²+b²-c²+c²-a²
=0

Answer 2

If [math] a+b+c=0, a^3+b^3+c^3=3 [/math] and [math] a^5+b^5+c^5=10 [/math] then [math] a^4+b^4+c^4 [/math] is?
5,058 Views