Question

show that (a-b) (a+b) + (b-c) (b+c) + (c-a) c+a)=0​

Answer 1

Step-by-step explanation:

a(a-b ) + b ( a -b) + b ( b-c) + c ( b-c) + c ( c-a) + a ( c-a)

(By multiplying)

a^2 - ab + ab - b^2 + b^2 - bc + bc - c^2 + c^2 - ac + ac - a^2

So, by cutting we get,

0

Hence proved

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