show that
(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0
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Answer:
Answered by
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Step-by-step explanation:
(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)
=> a^2-b^2+b^2-c^2+c^2-a^2
=> 0
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