Question

Show that :( a - b) (a + b) +(b - c)( b+ c) + ( c - a)( c + a) = 0​

Answer 1

Answer:

a²-b²+b²-c²+c²-a²

0

___________________________

Answer 2

Answer:

(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a) = 0

we know the identity (x-y)(x+y) = x²-y²

by this we get -

a²-b²+b²-c²+c²-a² = 0

0 = 0

hope this helps you !!!