Question

show that (a-b) (a+b) + (b-c) ( b+c) + (c-a) (c+a) =0.​

Answer 1

Step-by-step explanation:

{(a+b)(a-b)}=a^2-b^2 equation 1

similarly

(b-c)(b+c)=b^2-c^2 equation 2

similarly

(c-a)(c+a)=c^2-a^2. equation 3

a^2-b^2+b^2-c^2+c^2-a^2

on cancelling negative and positive

we get =0

hence proove

thanks

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