show that (a-b) (a+b) + (b-c) ( b+c) + (c-a) (c+a) =0.
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Step-by-step explanation:
(a-b)(a+b)=a²-b²
(b-c)(b+c)=b²-c²
(c-a)(c+a)=c²-a²
a²-b²+b²-c²+c²-a²
a²-a²-b²+b²-c²+c²
0-0+0-0
0
ritaarjun335:
their are opposite signs of each rerm
term
so they cancels out
hence proved
have u got it.
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