Question

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(a-b) (a+b)+(b-c) (b+c)+(c-a) (c-a) = 0​

Answer 1

a

$( a {}^{2} - b {}^{2} + b {}^{2} - c {}^{2} \ + c {}^{2} - a {}^{2} ) = 0$

Solve this

Answer 2

=(a-b)+(b-c) +(c-a) (all are in square)

Step-by-step explanation:

=a-b+b-c+c-a(all are in square) =(a-b) +(b-b)+(c-c) =0+0+0 RHS