Question

Show that
(a-b)(a-b)+(b-c) (b+c)+(c-a)(c+a)=0​

Answer 1

(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)

= a²- b²+ b²- c²+ c² - a²

= a² - a²- b² + b² - c² + c²

= 0+0+0

= 0

Hence proved.

I hope this answer helps you.