show that (a-b) (a+b) +(b-c) (b-c) +(c-a) (c+a) =0
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Step-by-step explanation:
LHS = (a-b) (a+b) + (b-c) (b+c) + (c-a) (c+a)
= a²- b² + (b-c)² + c² - a²
= a² - b² + b² - c² + c² - a²
= a² - a² + b² - b² + c² - c²
= 0
= RHS
∴ LHS = RHS
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