Question

Show that (a – b) (a + b) + (b – c) (b + c) + (c – a) (c + a) = 0​

Answer 1

Step-by-step explanation:

to prove : (a – b) (a + b) + (b – c) (b + c) + (c – a) (c + a) = 0​

take LHS,

= (a – b) (a + b) + (b – c) (b + c) + (c – a) (c + a)

= a²-b² + b²-c² + c²-a²

= a²--a² -b² + b² -c² + c²

= 0

= RHS

=> LHS =  RHS

Hence proved

Answer 2

Step-by-step explanation:

Hope it helped

Its always 0