Question

show that
(a-b) (a+b) + (b-c) (b+c) + (c-a) (c+a) = 0
please give me answer​

Answer 1

Answer:

this is very nice question ⁉️

Answer 2

Answer:

LHS

(a-b) (a+b) (b-c) (b+c) (c-a) (c+a)

=(a-b)^2 (b-c)^2 (c-a)^2

= a^2 b^2 + b^2 - c^2 + c^2 - a^2

=0