Question

Show that : (a + b) (a - b) + (b - c) (b + c) + (c -a) (c + a) = 0

Your answer


Show that : (a + b) (a - b) + (b - c) (b + c) + (c -a) (c + a) = 0​

Answer 1

Answer:

Step-by-step explanation:

$(a+b)(a+b) + (b-c)(b+c) + (c-a)(c+a)$ = $0$

Using  $(x+y)(x-y) = x^{2} - y^{2}$

$(a^{2} - b^{2}) + (b^{2} - c^{2}) + (c^{2} - a^{2})$ = $0$

$(a^{2} - a^{2}) + (b^{2} - b^{2}) + (c^{2} - c^{2}) = 0$

0 = 0

Hence proved