Question

Show that : (a + b) (a - b) + (b - c) (b + c) + (c -a) (c + a) = 0

Your answer


Show that : (a + b) (a - b) + (b - c) (b + c) + (c -a) (c + a) = 0​

Answer 1

Answer:

We know that (a + b) (a -b)=a^2- b^2

so,l.h.s= a^2 -b^2 +b^2 - c^2 + c^2 -a^2

=0

=r.h.s

if you think this is correct than

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