Question

Show that (a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)

Answer 1

= (a-b) (a+b) + (b-c)(b+c) + (c-a)(c+a)

= a^2-b^2 + b^2 - c^2 + c^2 - a^2

= 0

Answer 2

Answer:

= 0

Step-by-step explanation:

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