Question

Show that (a - b) + (b - c) + (c-a) = 3 (a - b) (6 - c) (e - a)




please I need it urgently​

Answer 1

Answer:

let a=(a-b)

b=(b-c)

c=(c-a)

{we know that a+b+c-3abc}

(a-b) + ( b-c)+ (c-a) - 3(a-b)(b-c)(c-a)=0

(a-b) + (b-c) + (c-a)=3(a-b)(b-c)(c-a)