show that a.[(b+c)×(a+b+c)]=0
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Answered by
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Step-by-step explanation:
- (ab+ac)(a2+ab+ac)=0 here 2 =square, using this formula you can solve problems
Answered by
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Answer:
Step-by-step explanation:
a.[(b+c)×(a+b+c)]
a.( b x a + b x b + b x c +c x a + c x b +c x c )
=a. ( b x a + 0 + b x c + c x a -b x c + 0)
= a.( -a x b + c x a)
=a.( -c +b)
= -a.c + a.b
=-ac cos 90+ab cos90
=-0+0
=0
proved
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