Show that A×(B+C) + B×(C+A) + C×(A+B) = 0.
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Answer:
AB + AC + BC + BA + CA + CB=0
2AB +2AC +2 BC= 0
2(AB+BC+AC) =0
AB+ BC + CA=0
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=>A×(B+C)+B×(C+A)+C×(A+B)=0
=>AB+AC+BC+AB+AC+BC=0
=>2(AB+BC+AC)=0
=>AB+BC+AC=0
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