Question

show that a+(b+c)+b(c+a)+c(a+b)=0​

Answer 1

Step-by-step explanation:

(ab) +(ac) +(bc) + (ba) + (ca)+ (cb) + (bc) + (cb)

cancel like terms: (ab,ba) (ac,ca) (bc,cb)

=0

hence,0=0

LHS = RHS