Show that a+√b is irrational??
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1
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Step-by-step explanation:
Let us assume √a + √b is rational.
Let √a + √b = p/q , where p,q are
integers and q ≠ 0.
√a = p/q - √b
Square both sides of the equation,
we get
a = p²/q² - 2p√b/q + b
=> 2p√b/q = p²/q² + b - a
=> 2p√b/q = ( p² + bq² - aq² )/q²
=> √b = [(q/2p )( p² + bq² - aq² )]/q²
=> √b = ( p² + bq² - aq² )/q
Since , p,q are integers (p²+bq²-aq²)/q is
rational , so √b is rational.
This contradicts the fact that √b is
irrational .
Hence , √a - √b is irrational .
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1
Answer:
Step-by-step explanation:
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