Question

show that a diagonal of a parallelogram divides it into two triangle of equal area​

Answer 1

Step-by-step explanation:

ANSWER

Here, ABCD is a parallelogram and BD is diagonal.

In △ADB and △CBD

AD∥BC

⇒ ∠ADB=∠CBD [ Alternate angles ]

Also AB∥DC

⇒ ∠ABD=∠CDB [ Alternate angles ]

⇒ DB=BD [ Common side ]

∴ △ADB≅△CBD [ By SAS congruence rule ]

Since congruent figures have same area.

∴ ar(ADB)=ar(CBD) [ Hence, proved ]

∴ We have proved that a diagonal divides a parallelogram into two triangles of equal area.

Answer 2

Step-by-step explanation:

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